Question

Люди добрые помогите с вопросами

Answer 1

f`(x)=(2cos(2x))`=2*(-sin(2x)=-2*sin(2*(-π/4)=-2*sin(-π/2)=-2*(-1)=2.  
y`=(4*ln(x+1)+log₃(5x))`=4/(x+1)+1/(5x*ln3).
(1/((x^3)^(1/5))`=(x^(-3/5)`=(-3/5)*(x^(-3/5-1)=
(-3/5)*(x^(-8/5)=-3/(5*x^8)^1/5).