Question

sin 2 x – 0,5 sin 2x=0

Answer 1

$sin^ 2x - 0,5 sin 2x=0\ sin^2x-0.5*2sinxcosx=0\ sin^2x-sinxcosx=0|:cos^2x\ tg^2x-tgx=0\tgx(tgx-1)=0\ tgx=0,x=pi n\ tgx=1,x=frac{pi}{4}+pi k$