Question

Y'=tgx *tgy reshite pojaluysta eto zadaniye

Answer 1

$y'=tgx*tgy \ frac{dy}{dx} =tgx*tgy \ frac{dy}{tgy}=dx*tgx \ frac{cosy*dy}{siny}= frac{sinx*dx}{cosx} \ intfrac{d(siny)}{siny}=-intfrac{d(cosx)}{cosx} \ lnsiny=-lncosx+lnC \ y= frac{C}{cosx}$