Question

cos^2 (3x-п/6)=3/4

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Answer 1

cos^2(3x-п/6)=3/4

cos(3x-п/6)=+-sqrt(3)/2

[3x-п/6=п/6+2пn; n e Z;

[3x-п/6=-п/6+2пn; n e Z;

 

[3x=п/3+2пn; n e Z;

[3x=2пn; n e Z;

Ответ: 

[x=п/9+(2пn)/3; n e Z;

[x=(2пn)/3; n e Z;