Question

Вычислите, пожалуйста :.С

Answer 1

log1/9 ∛3/3 =log (3)⁻²  3^1/3 /3 = -1/2 log 3  3^-2/3 = -1/2*-2/3* log3 3=1/3
 12^(log144 4 + log12 2)=12^log12 2 * log^12 2= 2*2=4
(log3 27 -log3 8) / log3 9/4 =log3 (3/2)^3/ log3 (3/2)^2 =3/2 *(log3 3/2/log3 3/2)=3/2