Question

помогите решить sin^2x=sinx

Answer 1

$sin^2 x=sin x, \ sin^2 x-sin x=0, \ sin x(sin x-1)=0, \ left [ {{sin x=0,} atop {sin x-1=0;}} right. left [ {{sin x=0,} atop {sin x=1;}} right. left [ {{x=pi n, nin Z} atop {x=frac{pi}{2}+2pi n, ninZ;}} right.$

Answer 2

а что за sinx1&