Предмет: Физика, автор: Marr11

Наклонный транспортёр поднимает груз массой 2 т на высоту 5 м за 20 с. определите кпд установки если мощность мотора транспортёра 25 кВт

Ответы

Автор ответа: kuperone1987

0

A=mgh=2000*5*9,81=98100 Дж.
N1=A/t=4905 Вт
n=N1/N *100%=19,62%

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