Question

решите логарифмическое неравенство log4 (8x+1)<=2

Answer 1

$log_4 (8x+1) leq 2$
ОДЗ: 
$8x+1 textgreater 0$
$8x textgreater -1$
$x textgreater -0.125$
$log_4 (8x+1) leq log_416$
$8x+1 leq16$
$8x leq15$
$x leq 1.875$

-------------------------[1.875]----------------
//////////////////////////////

--------(-0.125)---------------------------------
                /////////////////////////////////////////
 
Ответ: (-0.125;  1.875]