Question

t^4-1/5t^2+1/100=0
Помогите

Answer 1

T^4-1/5t^2+1/100=0
D=1/25-4*1/100=0
(t^2-1/10)^2=0
t^2=1/10
t1=√(1/10)=√(10)/10
t2=-√(1/10)=-√(10)/10