Question

Решите срочно надо :

Answer 1

$a);left(frac15right)^{x^2+x-10}=625\5^{-x^2-x+10}=5^4\-x^2-x+10=4\x^2+x-6=0\D=1+4cdot6=25\x_1=-3,;x_2=2\\b);log_{frac13}(4x+5)=-1\log_{3^{-1}}(4x+5)=-1\-log_3(4x+5)=-1\log_3(4x+5)=1\4x+5=3\4x=-2\x=-frac12\\c);5^x+5^{x+2}=26\5^x+5^2cdot5^x=26\26cdot5^x=26\5^x=1\x=0$