Question

докажите тождество (2а+5)(а^2-3а+2)+(4-а)(2а^2+7а+17)=78

Answer 1

(2а+5)(а²-3а+2)+(4-а)(2а²+7а+17)=78
2а³-6а²+4а+5а²-15а+10+8а²+28а+68-2а³-7а²-17а=78