Предмет: Математика, автор: dexter919

Логарифмы! Очень срочно надо 6.39 и 6.41,нужно решение

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Ответы

Автор ответа: arsenlevadniy
0
log_{0,1}(x^2-x-2) textgreater  log_{0,1}(3-x), \ left{begin{array}{c}x^2-x-2 textgreater  0,\3-x textgreater  0,\x^2-x-2 textless  3-x,end{array}right.  left{begin{array}{c}(x+1)(x-2) textgreater  0,\x-3 textless  0,\x^2-5 textless  0,end{array}right. \ left{begin{array}{c}(x+1)(x-2) textgreater  0,\x-3 textless  0,\(x+sqrt{5})(x-sqrt{5}) textless  0,end{array}right.   left{begin{array}{c} left [{{x textless  -1,} atop {x textgreater  2,}} right.\x textless  3,\-sqrt{5} textless  x textless  sqrt{5},end{array}right. \  left [ {{-sqrt{5} textless  x textless  -1},} atop {2 textless  x textless  sqrt{5};}} right. \ xin(-sqrt{5};-1)cup(2;sqrt{5}).

log_{0,1}(4-x) geq log_{0,1}10-log_{0,1}(x-1), \ log_{0,1}(4-x)+log_{0,1}(x-1) geq log_{0,1}10, \ log_{0,1}(4-x)(x-1) geq log_{0,1}10, \ left{begin{array}{c}4-x textgreater  0,\x-1 textgreater  0,\(4-x)(x-1) leq 10;end{array}right.  left{begin{array}{c}x-4 textless  0,\x-1 textgreater  0,\x^2-5x+4 geq 10;end{array}right.  left{begin{array}{c}x textless  4,\x textgreater  1,\x^2-5x-6 geq 0;end{array}right.
left{begin{array}{c}x textless  4,\x textgreater  1,\(x+1)(x-6)geq 0;end{array}right.  left{begin{array}{c}1<x<4,\ left [ {{x leq -1,} atop {x geq 6;}} right.end{array}right. \ xinvarnothing.
Автор ответа: dexter919
0
Спасибо огромное
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