Question

Возведите в степень:
1) (7p^3+9q^4)^3;
(10x^3+1/3a^2)^2;
(0,3a^5+0,5b^2)^3;

Answer 1

= 343p^9 + 729p^12;
= 100x^6 + 1/9a^4;
= 0.027a^15 + 0.125b ^6;