Question

Решите уравнение 5y^4-8y^2+3=0

Answer 1

5y^4 - 8y^2 + 3 = 0 
y^2 = t
5t^2 - 8t + 3 = 0 
D = 64  - 4*3*5 = 2^2
t1 = ( 8 + 2)/10 = 10/10 = 1
t2 = ( 8 - 2)/10 = 3/5 = 0.6

y^2 = 1
y1 = - 1
y2 = 1

y^2 = 0.6
y3 = - √0.6
y4 = √0.6

Answer 2

5y⁴-8y²+3=0
y²=a
5a²-8a+3=0
D=64-60=4
a=6:10=0,6
a=10:10=1
y²=a
1)y²=0,6
y=√0,6
y=-√0,6
2)y²=1
y=1; y=-1