Question

Решить уравнения.
1)$frac{1}{25} x^{2} -36=0$
2)(2x-1)(8x+3)-(3x-1)(4x+1)=8

Answer 1

$1) frac{1}{25}x^2-36=0 \ x^2=900 \ x_{1}=30 \ x_{2}=-30 \ \ 2) (2x-1)(8x+3)-(3x-1)(4x+1)=8 \ 16x^2+6x-8x-3-12x^2+x+1=8 \ 4x^2-x-10=0 \ D=1+160=161 \ x_{1}= frac{1- sqrt{161} }{8} \ x_{2} = frac{1+sqrt{161} }{8}$