Question

решите данные неравенства

Answer 1

2) cos(x/3)>√3/2, (x/3)∈(-π/6 +2πk; π/6 +2πk), k∈Z
    x∈(-π/2+6πk; π/2+6πk), k∈Z
3) 2cosx -√3≤0, 2cosx≤√3, cosx≤(√3/2),
    x∈[π/6 +2πk; 11π/6 +2πk], k∈Z

Answer 2

1уравнение)   x/3≥√3/2⇒x/3≥pi/6+2Pi n n∈Z либо 11pi/6 +2Pi k k∈Z
1)x/3≥pi/6+2Pi n n∈Z ║*3
x≥Pi÷2+6Pin n∈Z
2)x/3≥11pi/6 +2Pi k k∈Z║×3
x≥11Pi/2+6Pi k k∈Z
2) Ур-ие 
2cosx-√3≤0
2cosx≤√3
cosx≤√3÷2
cost≤Pi/6