Предмет: Химия, автор: YURIPLESTESKY

Сахар массой 25г растворили в воде объёмом 500мл. Определите массовую долю сахара в полученном растворе

Ответы

Автор ответа: SashaB11

W (сахара) = m (сахара) : m раствора
m (р-ра) = m (воды) + m (сахара)
Зная, что плотность воды 1г/мл, то m воды равна 500г.
m (р-ра) = 500г + 25г = 525г
w (сахара) = 25 : 525 = 0,047 * 100% = 4,7%

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