Question

Опишите пж подробно. 564

Answer 1

$1);19frac56-6frac1{12}-2frac79=19frac{30}{36}-6frac3{36}-2frac{28}{36}=\=(19-6-2)+left(frac{30}{36}-frac{3}{36}-frac{28}{36}right)=11-frac1{36}=10frac{35}{36}\\2);11frac7{10}-5frac7{30}-3frac4{15}=11frac{21}{30}-5frac7{30}-3frac8{30}=\=(11-5-3)+left(frac{21}{30}-frac{7}{30}-frac{8}{30}right)=3+frac6{30}=3+frac15=3frac15\\3);9frac{14}{15}-2frac15-4frac7{10}=9frac{28}{30}-2frac6{30}-4frac{21}{30}=$
$=(9-2-4)+left(frac{28}{30}-frac{6}{30}-frac{21}{30}right)=3+frac1{30}=3frac1{30}\\4);20frac38-left(6-2frac16right)=20frac38-3frac56=20frac9{24}-3frac{20}{24}=\=(20-3)+left(frac9{24}-frac{20}{24}right)=17-frac{11}{24}=16frac{13}{24}\\5);28frac1{20}-left(7-2frac8{15}right)=28frac1{20}-4frac7{15}=28frac3{60}-4frac{28}{60}=\=(28-4)+left(frac3{60}-frac{28}{60}right)=24-frac{25}{60}=24-frac5{12}=23frac7{12}$
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$6);29frac3{25}-left(4-2frac15right)=29frac3{25}-1frac45=29frac3{25}-1frac{20}{25}=\=(29-1)+left(frac3{25}-frac{20}{25}right)=28-frac{17}{25}=27frac8{25}$