Question

Решите уравнение: (3x^2)^2∗(2x^2)^3/(6x)^3∗x^4=72.

Answer 1

(3x²)² *(2x⁻²)³ *(6x)³ *x⁻⁴ = 72
9x⁴ * 8x⁻⁶ * 216x⁻¹ = 72
216x⁻³ = 1
x⁻³ = 1/216
1/x³ = 1/6³
x = 6
(3x²)² *(2x²)³ *(6x)⁻³ *x⁻⁴ = 72
9x⁴ * 8x⁶ * 1/216 * x⁻⁷ = 72
x³ * 1/216 = 1
x³ = 216
x³ = 6³
x = 6