Question

√3sinx+√3cosx=0
tg(x-П/4)=1

ПОМОГИТЕ!!!

Answer 1

√3sinx+√3cosx=0/cosx
√3tgx+√3=0
tgx=-1
x=-π/4+πn,n∈z

tg(x-π/4)=1
x-π/4=π/4+πn
x=π/2+πn,n∈z