Question

2x^2-3x-5=0 2x^2-3x-2=0. 2x^2+5x-3=0

Answer 1

2x² - 3x - 5 = 0
D = 9 + 5•2•4 = 49 = 7²
x1 = (3 + 7)/4 = 2,5
x2 = (3 - 7)/4 = -1

2x² - 3x - 2 = 0
D = 9 + 2•2•4 = 25 = 5²
x1 = (3 + 5)/4 = 2
x2 = (3 - 5)/4 = -1/2

2x² + 5x - 3 = 0
D = 25 + 3•2•4 = 49 = 7²
x1 = (-5 + 7)/4 = 1/2
x2 = (-5 - 7)/4 = -3.