Question

2x/x^2-1=x/x+1+x/x-1

Answer 1

$xneqб1\frac{2x}{x^2-1}=frac{x}{x+1}+frac{x}{x-1}=frac{x(x-1)}{(x+1)(x-1)}+frac{x(x+1)}{(x-1)(x+1)}=frac{x(x-1)+x(x+1)}{x^2-1}\\2x=x(x-1+x+1)\2x=2x^2\x-x^2=0\x(x-1)=0\x=0$