Question

найти dy/dx
$y=sin sqrt{x} /arcsin x^{3}$

Answer 1

u=sin√x   v=arcsinx³   y'=(u/v)'=(1/v²)(u'v-v'u)
u'=cos√x*(1/2√x)    v'=1/√(1-x⁶)*3x²

y'=(1/arcsin²x³)*[(0.5*cos√x/√x)arcsinx³-sin√x(3x²/√(1-x⁶))]