Предмет: Физика, автор: kasymoffvova2

Чему равна ёмкость батареи конденсаторов, соединённых по заданной схеме, если ёмкость каждого по 2мкФ?

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Ответы

Автор ответа: Аноним

0

Конденсаторы С1 и С2 соединены ПОСЛЕДОВАТЕЛЬНО, поэтому:
C12 = C1*C2 / (C1+C2) = 2*2/ (2+2) = 1 мкф

С12 и С3 соединены ПАРАЛЛЕЛЬНО, поэтому емкость батареи
C = C12 + C3 = 1+2 = 3 мкФ

Автор ответа: kasymoffvova2

0

Спасибочки большое

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