Question

Найти 0 функции
у = log3(х2+5)−2
у = 4х - 3×2х – 4
у = √х2−4х+3

Answer 1

$1) log_3(x^2+5)-2=0\\log_3(x^2+5)=2\\3^2=x^2+5\\9=x^2+5\\x^2-4=0\\(x+2)(x-2)=0\\x_1=-2\\x_2=2\\2)4x-3cdot 2x-4=0\\4x-6x-4=0\\-2x-4=0\\-2x=4\\x=-2$

$displaystyle 3) sqrt{x^2-4x+3}=0\\x^2-4x+3=0\\x_{1,2}= frac{4pm sqrt{16-12} }{2}= frac{4pm 2}{2} =3,1$

Answer 2

спасибо)