Question

Решите неравенство f'(x)> 0:
a) f(x)= -8x^ - 2x + 1;

в) f(x)= 1 + x - 6x^

Answer 1

$1)quad f(x)=-8x^2-2x+1\\f'(x)=-16x-2 textgreater 0; ; to ; ; 16x textless -2; ,; ; x textless -frac{1}{8}\\2)quad f(x)=1+x-6x^2\\f'(x)=1-12x textgreater 0; ; to ; ; 12x textless 1; ,; ; x textless frac{1}{12}$