Question

Решите пожалуйста
|√8-3|= ?
√(√17-4)^2

Answer 1

$|sqrt{8}-3|=-(sqrt{8}-3)=3-sqrt{8};\sqrt{(sqrt{17}-4)^2}=|sqrt{17}-4|=sqrt{17}-4$

Answer 2

$1)quad |sqrt8-3|=-(sqrt8-3)=3-sqrt8; ,\\; tak; kak; ; sqrt8 textless sqrt9; ,; ; sqrt8 textless 3; ; Rightarrow ; ; sqrt8-3 textless 0\\2)quad sqrt{(sqrt{17}-4)^2}=|sqrt{17}-4|=sqrt{17}-4; ,\\tak; kak; ; sqrt{17} textgreater sqrt{16}; ,; ; sqrt{17} textgreater 4; ; Rightarrow ; ; sqrt{17}-4 textgreater 0\\\P.S.quad sqrt{a^2}=|a|= left { {{a; ,; esli; a geq 0} atop {-a; ,; esli; a textless 0}} right.$