Question

Решить логарифмическое нравчтво log1/2(log2√6-x)>0

Answer 1

$log_{frac{1}{2} }(log_2sqrt{6-x}) textgreater 0; ,\\ODZ:; left { {{log_2sqrt{6-x} textgreater 0} atop {x-6 textgreater 0}} right. ; left { {{sqrt{6-x} textgreater 1} atop {x textgreater 6}} right. ; left { {{6-x textgreater 1} atop {x textgreater 6}} right. ; left { {{x textless 5} atop {x textgreater 6}} right. ; ; ; xin varnothing \\Otvet:; ; xin varnothing ; .$