Question

разрешите неравенство))))))))

Answer 1

1)
$0,1^x leq 0,01\0,1^x leq 0,1^2\x geq 2$
2)
$frac{1}{3} ^{x^2-4x+3} geq frac{1}{3} ^{x-1}\x^2-4x+3 leq x-1\x^2-5x+4 leq 0\(x-1)(x-4) leq 0$
x∈[1;4]