Question

log π log 2 log 7 x=0

Answer 1

1 = π^0 = log2(log7(x))
log2(log7(x)) = 1
2^1 = log7(x)
log7(x) = 2
7^2 = x
x = 49

Answer 2

почему 2^1=log7(X)&

Answer 3

по определению логарифма

Answer 4

спасибо