Предмет: Физика, автор: Kdksjdsj274993

Помогите пожалуйста задачу!!!!!!!!!!Я дам 34 балла!!!!!
Пружина длиной 2см при нагрузке 15 Н удлиняется на 3мм.Найдите длину пружины при нагрузке 200 Н?

Ответы

Автор ответа: tana20101997

0

x1=F1/k
x2=F2/k
x1/x2=F1/F2
x2=F2*x1/F1=200*3/15=40 мм

Автор ответа: Kdksjdsj274993

0

Спасибо!!

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