Question

log3(основание)^2x-log3x-6=0

Answer 1

log^2 (3)х -log(3)х-6=0

1)log(3)х = - 2
х=3^(-2)
х1=19
log(3)х=3
х=3^3
х2=27

Answer 2

log₃²x - log₃x -6 = 0
a = log₃x 
a² - a - 6 = 0
a₁=-2             a₂=3
log₃x=-2       log₃x=3  
x₁=3⁻²=1/9       x₂=3³=27