Question

log4(x-4)+log4(x-1)=1

Answer 1

$log _{4} (x-4)+log_{4}(x-1)=1 \ left { {{x-4 textgreater 0} atop {x-1 textgreater 0}} right. left { {{x textgreater 4} atop {x textgreater 1}} right. x textgreater 4 \ log _{4} (x-4)(x-1)=log _{4}4 \ (x-4)(x-1)=4 \ x^{2} -x-4x+4-4=0 \ x^{2} -5x=0 \ x(x-5)=0 \ x=0, x=5$ x=0 - посторонний корень. Ответ x=5