Предмет: Физика, автор: BossSancez99

пружина под действием силы 1500 Ньютонов удлинилась на 3 сантиметров Определите жесткость пружины

Ответы

Автор ответа: Skanejom

F=k×x
1500H=k×0.03m
k=1500/0.03=50000 Н/м³

Автор ответа: BossSancez99

А если как то поподробнее.

Автор ответа: Skanejom

1 строка - закон Гука

Автор ответа: Skanejom

А дальше математические преобразования

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