Question

5*3^2x-1 -9^x-0.5+3^2x+4*9^x-1=25

Answer 1

$5*3^{2x-1} - 3^{2x-1} + 3^{2x} +4*3 ^{2x-2} =25 5*3^{2x}/3-3^{2x}/3+3^{2x} +4*3^{2x}/9=25 \ 3^{2x}(5/3-1/3+1+4/9)=25 \ 3^{2x}(15/9-3/9+9/9+4/9)=25 \ 3^{2x}*25/9=25 \ 3^{2x}=9 \ 3^{2x}=3^2 \ 2x=2 \ x=1$