Question

Люди помогите заданни 13.77 A и B плиз

Answer 1

A
(tg7π/24-tgπ/24)(tg7π/24+tgπ/24)/(1+tg7π/24*tgπ/24)(1-tg7π/24*tgπ/24)=
=tg(7π/24-π/24)*tg(7π/24+π/24)=tgπ/4*tgπ/3=1*√3=√3
Б
1:[-(tg5π/24-tgπ/24)(tg5π/24+tgπ/24)/(1+tg5π/24*tgπ/24)(1-tg5π/24*tgπ/24)]=
=1:[-tg(5π/24-π/24)*tg(5π/24+π/24)]=1:[-tgπ/6*tgπ/4]=1:[1/√3*1]=-√3