Question

(х+4)^2=(2-x)^2 помогите решить уравнение

Answer 1

(х+4)²=(2-х)²
x²+8x+16=4-4x+x²
x²-x²+8x+4x+16-4=0
12x+12=0
12x=-12
x=-1

Answer 2

$x^{2} +8x+16 = 4-4x+x^{2} 12x = -12 x = -1$