Question

3*(у-6)-12*(у-1,5)=18

Answer 1

3y-18-12y+18-18=0
-9y-18=0
-9y=18
y=-18/9
y=-2

Answer 2

$3*(y-6)-12*(y-1,5)=18 \ 3y-18-12y+18=18 \ -9y=18 \ 9y=-18 \ y=-18:9 \ y=-2$