Question

Решите уравнение 50y-10y^2=55

Answer 1

$50y-10y^2=55\ -10y^{2}+50y-55=0\ D=b^{2}-4ac=50^{2}-4*(-10)*(-55)=300\ x_{1}= frac{-b+sqrt{D}}{2a} = frac{-50+sqrt{300}}{-20}= frac{5+sqrt{3}}{2} \ \ x_{2}= frac{-b-sqrt{D}}{2a} = frac{-50-sqrt{300}}{-20}= frac{5-sqrt{3}}{2}$