Question

z1=1+2i z2=3-4i найти z1/z2

Answer 1

(1+2i)/(3-4i) = (1+2i)(3+4i)/((3-4i)(3+4i)) = (3+6i+4i + 8i²)/(9-16i²) = 
(-5+10i)/25 = (2i - 1)/5