Question

log2(x+4x+3)=3 обратные тригономитрические функции

Answer 1

log [2](5x+3)=3
5x+3=8
5x=5
x=1

Answer 2

$log_2(x^2+4x+3)=3; ,\\ODZ:; ; x^2+4x+3 textgreater 0; ,; ; x_1=-3,; x_2=-1\\(x+3)(x+1) textgreater 0; ; to ; ; xin (-infty ,-3)cup (-1,+infty )\\x^2+4x+3=2^3\\x^2+4x-5=0\\x_1=-5; ,; x_2=1; ; in ODZ\\Otvet:; ; x=-5,; x=1; .$