Question

(a-4)²+(a-4)(a+4)+8a при а=-0,3

Answer 1

$(a-4)^2+(a-4)(a+4)+8a=a^2-8a+16+a^2-16+8a= \ =2a^2$
при а=-0,3
$2a^2=2(-0.3)^2=2*0.09=0.18$