Question

Помогите решить систему неравенств:
x^2-5x+6>=0
1/x < 1

Answer 1

$left { {{x^2-5x+6 geq o} atop {frac{1}{x} textless 1}} right. ; left { {{(x-2)(x-3) geq 0} atop { frac{1-x}{x} textless 0}} right. ; left { {{(x-2)(x-3) geq 0} atop {frac{x-1}{x}} textgreater 0} right. \\ left { {{xin (-infty ,2)cup (3,+infty )} atop {xin (-infty ,0)cup (1,+infty )}} right. ; ; to ; ; xin (-infty ,0)cup (1,2)cup (3,+infty )$