Question

log числа 9√3 по основанию √3

Answer 1

$log_{sqrt3}, 9sqrt3=log_{3^{1/2}}(3^2cdot 3^{1/2})= frac{1}{1/2}cdot log_33^{frac{5}{2}}=2cdot frac{5}{2} cdotunderbrace{log_33}_{1}=5$