Question

Решите систему уравнений
У-2Х=2
5Х^2-У=1

Answer 1

У=2+2х
5х^2-у=1

5х^2-(2+2х)=1
5х^2-2-2х=1
5х^(-2х)=1
-10х2=1
10х2=1
Х1=√1 х2=-√1
У1=4 у=0

Answer 2

$left { {{y-2x=2,} atop {5x^2-y=1;}} right. left { {{y=2x+2,} atop {5x^2-(2x+2)=1;}} right. left { {{y=2x+2,} atop {5x^2-2x-2-1=0;}} right. left { {{y=2x+2,} atop {5x^2-2x-3=0;}} right. \ 5x^2-2x-3=0, \ D_{/4}=(-1)^2-5cdot(-3)=1+15=16, \ x=frac{1pm4}{5}, \ x_1=-0,6, x_2=1; \ left { {{y=2x+2,} atop { left [ {{x=-0,6,} atop {x=1;}} right. }} right. left [ {{ left { {{x=-0,6,} atop {y=0,8;}} right. } atop { left { {{x=1,} atop {y=4.}} right. }} right.$