Question

вычислить arccos(-√3/2)+arcctg(1/√3)

Answer 1

$arccos(- frac{sqrt3}{2} )+arcctgfrac{1}{sqrt3}=(pi -arccos frac{sqrt3}{2})+frac{pi}{3}=\\=pi -frac{pi}{6}+frac{pi}{3}= frac{6pi -pi +2pi}{6} =frac{7pi }{6}$