Question

Y=корень(3х-7)(х+2)
Дробь
Х+3

Answer 1

$Y= frac{sqrt{(3x-7)(x+2)} }{x+3}\ (3x-7)(x+2) geq 0\ (3x-7)(x+2)=0\ 3x^{2}+2-7x+2=0\ 3x^{2}-7x+4=0\ D=b^{2}-4ac=49-48=1 sqrt {D}=sqrt{1}\ x_{1}= frac{-b+sqrt{D}}{2a} = frac{7+1}{6}= frac{8}{6} \ x_{2}= frac{-b-sqrt{D}}{2a} = frac{7-1}{6}=1\ x neq -3$