Предмет: Химия, автор: Sascha2384

ЗАДАЧА ПО ХИМИИ, РЕШИТЕ ПОЖАЛУЙСТА!!!!
35 БАЛЛОВ!
Найти массу оксида фосфора⁵ полученного при сгорании 31 грамма фосфора.

Ответы

Автор ответа: AnonimusPro

4P + 5O2 = 2P2O5;

M(P)= 31г/моль
следовательно количества фосфора в молях:
31г / 31г/моль=1 моль;

M(P2O5)=142 г/моль;
по уравнению реакции видно, что количество оксида фосфора в молях в 2 раза меньше, т.е 0,5 моль;

m(P2O5)=0,5*142=71г;
Ответ: 71 грамм

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