Question

РЕБЯТА,КТО-НИБУДЬ,ПРОШУ,ПОМОГИТЕ

Answer 1

$1); ; tcdot frac{t+ frac{2}{sqrt{t+4}} }{2-sqrt{t+4}} +sqrt{t+4}+ frac{4}{sqrt{t+4}} =tcdot frac{tcdot sqrt{t+4}+2}{sqrt{t+4}cdot (2-sqrt{t+4})} +frac{(t+4)+4}{sqrt{t+4}} =\\=frac{tcdot (tcdot sqrt{t+4}+2)+(t+8)(2-sqrt{t+4})}{sqrt{t+4}cdot (2-sqrt{t+4})} = frac{t^2cdot sqrt{t+4}+2t+2t+16-tcdot sqrt{t+4}-8cdot sqrt{t+4}}{sqrt{t+4}cdot (2-sqrt{t+4})} =\\= frac{t^2cdot sqrt{t+4}+4t-tcdot sqrt{t+4}-8cdot sqrt{t+4}+16}{sqrt{t+4}cdot (2-sqrt{t+4})}; ;$

$2); ; tcdot frac{1+ frac{2}{sqrt{t+4}} }{2-sqrt{t+4}} +sqrt{t+4}+ frac{4}{sqrt{t+4}} =tcdot frac{sqrt{t+4}+2}{sqrt{t+4}cdot (2-sqrt{t+4})} +frac{t+8}{sqrt{t+4}} =\\= frac{tsqrt{t+4}+2t+(2-sqrt{t+4})(t+8)}{sqrt{t+4}cdot (2-sqrt{t+4})} = frac{tsqrt{t+4}+4t+16-tsqrt{t+4}-8sqrt{t+4}}{sqrt{t+4}(2-sqrt{t+4})} =\\= frac{4t-8sqrt{t+4}+16}{sqrt{t+4}(2-sqrt{t+4})} =frac{4(t-2sqrt{t+4}+4)}{sqrt{t+4}(2-sqrt{t+4})}$