Question

а)2√2+√50-√98. б) (3√5-√20)√5. в) (√3+√2) во 2степени

Answer 1

$1) 2sqrt{2} + sqrt{50} - sqrt{98} = 2sqrt{2} + 5sqrt{2}-7sqrt{2} = 0 \ 2) (3sqrt{5} - sqrt{20}) * sqrt{5} = (3sqrt{5} - 2sqrt{5}) * sqrt{5} = sqrt{5} * sqrt{5} = 5 \ 3) (sqrt{3} + sqrt{2})^2 = 3 + 2sqrt{6} + 2=5 +2sqrt{6}$